list of list with ongoing enumeration

[fliff]

He everybody

I'd like to make a list of lists which takes a row of numbers (0 to 126) and makes a list every seventh number, so the list would look like:
list = [[0,1,2,3,4,5,6],[7,8,9,10,11,12,13],[14,15.....]]

i'd like to achieve this by using a loop..any ideas?

Thanks for your help, f.

[elParaguayo]

I apologise for the ugliness of this code - and I am sure there will be more "pythonic" ways of doing this, but this should work:

Code: Select all

a = range(126)
b = []
for i in range(0,126,7):
    b.append(a[i:i+7])
    
print b

returns:

Code: Select all

[[0, 1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12, 13], [14, 15, 16, 17, 18, 19, 20], [21, 22, 23, 24, 25, 26, 27], [28, 29, 30, 31, 32, 33, 34], [35, 36, 37, 38, 39, 40, 41], [42, 43, 44, 45, 46, 47, 48], [49, 50, 51, 52, 53, 54, 55], [56, 57, 58, 59, 60, 61, 62], [63, 64, 65, 66, 67, 68, 69], [70, 71, 72, 73, 74, 75, 76], [77, 78, 79, 80, 81, 82, 83], [84, 85, 86, 87, 88, 89, 90], [91, 92, 93, 94, 95, 96, 97], [98, 99, 100, 101, 102, 103, 104], [105, 106, 107, 108, 109, 110, 111], [112, 113, 114, 115, 116, 117, 118], [119, 120, 121, 122, 123, 124, 125]]

This is python 2.7.

[elParaguayo]

You could simplify all that into a list comprehension:

Code: Select all

b = [range(126)[i:i+7] for i in range(0,126,7)]
    
print b

[fliff]

Thanks, that's what i was looking for.