Indeed. Note that if the TVS bails out physically, the Pi is lucky if it is not toast/fried/ex/dead.Heater wrote: ↑Sat Sep 28, 2019 11:23 amI ran one of my Pi off a PSU brick that was adjustable in steps up to 18v.
One day the inevitable happened, the PSU got connected to the Pi when it was set to 12v. And smoke came out.
The Pi survived. Protected by the protection diode that jumped off the board.
Until I did it the second time...
All in all I would advise against using such a supply.
A 1K resistor should be enough load to set the voltage, unless the regulation is so poor that the supply is useless anyway. You could use a lower value resistor, but make sure it can dissipate the heat. Don't go below 600R at 12V with a 0.25W resistor, for example.pixelpop wrote: do you think 1K is enough of a load to get an accurate output voltage measurement?
Those I had until today were all adjustable at no-load, but the 10MΩ voltmeter.
Did the boost converter fail or did the adjustment screw get moved somehow?Heater wrote: ↑Sat Sep 28, 2019 11:23 amI ran one of my Pi off a PSU brick that was adjustable in steps up to 18v.
One day the inevitable happened, the PSU got connected to the Pi when it was set to 12v. And smoke came out.
The Pi survived. Protected by the protection diode that jumped off the board.
Until I did it the second time...
All in all I would advise against using such a supply.
Interestingly, I found a web site that does Watts/Volts/Amps/Ohms calculations (https://www.rapidtables.com/calc/electr ... lator.html) and if you plug in 2.5A and 5.2V, you get a resistance of just 2.08 ohms. Seems like a pretty light load.davidcoton wrote: ↑Sat Sep 28, 2019 1:54 pmA 1K resistor should be enough load to set the voltage, unless the regulation is so poor that the supply is useless anyway. You could use a lower value resistor, but make sure it can dissipate the heat. Don't go below 600R at 12V with a 0.25W resistor, for example.
A light load is all that is necessary to tame the PSU output -- probably don't need anything, but it will help discharge the output capacitors. You are not trying to do a full load test, just avoid no-load (which should be alright, but then, why the warning?).pixelpop wrote: ↑Sat Sep 28, 2019 4:21 pmInterestingly, I found a web site that does Watts/Volts/Amps/Ohms calculations (https://www.rapidtables.com/calc/electr ... lator.html) and if you plug in 2.5A and 5.2V, you get a resistance of just 2.08 ohms. Seems like a pretty light load.davidcoton wrote: ↑Sat Sep 28, 2019 1:54 pmA 1K resistor should be enough load to set the voltage, unless the regulation is so poor that the supply is useless anyway. You could use a lower value resistor, but make sure it can dissipate the heat. Don't go below 600R at 12V with a 0.25W resistor, for example.
Use a good USB cable or wire directly to the Ov-5v test points.
I'll give that a try. I am just using breadboard jumper wires now, but I'll beef it up to production (18 gauge) wiring.
I used this setting based on Adafruit setting all their power adapters to 5.25V. "This adapter was specifically designed to provide 5.25V not 5V, but we still call it a 5V USB adapter. We did this on purpose to solve a problem that occurs often with USB-powered gadgets: they draw so much current than the resistance of the cable causes a voltage drop, so instead of 5V, the device sees 4.75V or so."
I haven't used it that much since I got it, but I'm going to give it a good charge on a charger tonight.

1. Lithium cells are not fully charged at the factory.pixelpop wrote: ↑Sun Sep 29, 2019 8:55 amI haven't used it that much since I got it, but I'm going to give it a good charge on a charger tonight.
According to the DigiKey calculator (https://www.digikey.com/en/resources/co ... ttery-life), I should get about 40 minutes (0.7 hours) with 5V and 3A with this battery (3000 uAh):
Battery Life = Battery Capacity in mAh / Load Current in mA * 0.70
*The factor of 0.7 makes allowances for external factors which can affect battery life.