else and elif syntax error [solved]

[helpthepi]

i was using python 3.4.2 today and while creating a program ran into the problem that else and elif was not defined. WHY! do not get it. here is the code i was using:
SCROLL DOWN FOR EDITED CODE

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
  print("cool")
print("Admin(s) let the players answer the questions")  
elif RLG== "N":
  print("ok..")
print("that is fine but here are the rules")
else:
    print("sorry did not regonise answer")

EDITED CODE:

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
  print("cool")
print("Admin(s) let the players answer the questions")  
elif RLG== "N":
  print("ok..")
print("that is fine but here are the rules")
else:
    print("sorry did not regonise answer")

[Ernst]

I do not know much about python but I can see your mistake.
Take a close look and you should be able to identify the problem with your code.

[helpthepi]

I do not know much about python but I can see your mistake.
Take a close look and you should be able to identify the problem with your code.

I cant see anything

[DougieLawson]

i was using python 3.4.2 today and while creating a program ran into the problem that else and elif was not defined. WHY! do not get it. here is the code i was using:

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
  print("cool")
print("Admin(s) let the players answer the questions")  
elif RLG== "N":
  print("ok..")
print("that is fine but here are the rules")
else:
    print("sorry did not regonise answer")

If that's an exact facsimile of your code then you've got some serious indentation problems.

[scotty101]

Your indentation is incorrect.

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
    print("cool")
    print("Admin(s) let the players answer the questions")  
elif RLG== "N":
    print("ok..")
    print("that is fine but here are the rules")
else:
    print("sorry did not regonise answer")

[SkyRise]

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
  print("cool")
  print("Admin(s) let the players answer the questions") 
elif RLG== "N":
  print("ok..")
  print("that is fine but here are the rules")
else:
  print("sorry did not regonise answer")

(Edit: the last line's indent was wrong too)

[DirkS]

I do not know much about python but I can see your mistake.
Take a close look and you should be able to identify the problem with your code.

I cant see anything

Indentation. The second (and fourth) print statement ends the if block, so the elif after that will generate an error

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
  print("cool")
  print("Admin(s) let the players answer the questions")  
elif RLG== "N":
  print("ok..")
  print("that is fine but here are the rules")
else:
    print("sorry did not recognise answer")

See e.g. http://www.python-course.eu/python3_blocks.php and googling for 'python indentation' will give you a lot of hits.

[helpthepi]

Your indentation is incorrect.

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
    print("cool")
    print("Admin(s) let the players answer the questions")  
elif RLG== "N":
    print("ok..")
    print("that is fine but here are the rules")
else:
    print("sorry did not regonise answer")

I know it is wrong i am new to python!
how should the indentation be then

[helpthepi]

EDIT:
Edited the indentation still error message new code:

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
  print("cool")
print("Admin(s) let the players answer the questions")  
elif RLG== "N":
  print("ok..")
print("that is fine but here are the rules")
else:
    print("sorry did not regonise answer")

[Ernst]

http://www.python-course.eu/python3_blocks.php

[helpthepi]

http://www.python-course.eu/python3_blocks.php

i have read it and edited code. Thank you. But a new problem is that it prints the else command even though it should do the if or elif. Here is new code:

Code: Select all

RLG=input(" Welcome RLG Gamers is there a admin with you? Y or N")
if RLG== "Y":
  print("cool")
  print("Admin(s) let the players answer the questions")  
elif RLG== "N":
  print("ok..")
  print("that is fine but here are the rules")
else:
    print("sorry did not recognise answer")
 

if i type in for the input Y it prints: sorry did not recognise answer
same with it if i enter N for the input.

[hippy]

if i type in for the input Y it prints: sorry did not recognise answer
same with it if i enter N for the input.

Probably because you are pressing the Y or N key without holding down the shift key. That will return "y" or "n" not "Y" or "N".

There are a number of ways to force an uppercase character or to match for either upper or lowercase. One solution is ...

if RLG.upper() == "Y":
elif RLG.upper() == "N":

You can add a print command (function) to show what is actually in your RLG variable if that is not the problem.

[Ernst]

http://www.python-course.eu/input.php

[DirkS]

I know it is wrong i am new to python!
how should the indentation be then

I posted your code with corrected indentation...

[Ernst]

What I know about Python is little, with a little bit of effort I came up with this:

Code: Select all

RLG=raw_input(" Welcome RLG Gamers is there a admin with you? Y or N").upper()
if RLG=="Y":
  print("cool")
  print("Admin(s) let the players answer the questions")
elif RLG== "N":
  print("ok..")
  print("that is fine but here are the rules")
else:
  print("sorry did not recognise answer")

[helpthepi]

if i type in for the input Y it prints: sorry did not recognise answer
same with it if i enter N for the input.

Probably because you are pressing the Y or N key without holding down the shift key. That will return "y" or "n" not "Y" or "N".

There are a number of ways to force an uppercase character or to match for either upper or lowercase. One solution is ...

if RLG.upper() == "Y":
elif RLG.upper() == "N":

You can add a print command (function) to show what is actually in your RLG variable if that is not the problem.

No i do use shift this is what comes in the shell

Code: Select all

Python 3.4.2 (default, Oct 19 2014, 13:31:11) 
[GCC 4.9.1] on linux
Type "copyright", "credits" or "license()" for more information.
>>> ================================ RESTART ================================
>>> 
 Welcome RLG Gamers is there a admin with you? Y or N Y
sorry did not recognise answer
>>> RLG
' Y'
>>> 

why does this happen?

[Ernst]

Do you notice the space character ?

Code: Select all

' Y'

[helpthepi]

Do you notice the space character ?

Code: Select all

' Y'

WOW. did not realise python was that sensitive.
it solved it. Thanks

[helpthepi]

how do i mark this post as solved

[scotty101]

Do you notice the space character ?

Code: Select all

' Y'

WOW. did not realise python was that sensitive.
it solved it. Thanks

All languages are that sensitive. It isn't a python thing. "AB" is not equal to "B", why would " Y" be equal to "Y"?

[klintkrossa]

Hello,
This is my two-bits.

Code: Select all

RLG = input(" Welcome RLG Gamers is there a admin with you? Y or N")
RLG = RLG.upper()
if RLG == "Y":
  print("cool \n Admin(s) let the players answer the questions")  
elif RLG== "N":
  print("ok.. \n that is fine but here are the rules")
else:
    print("Sorry did not recognise answer")

RGL.upper() will clean up the input error you may get if they type "y"
The "\n" is a new line.

[mahjongg]

marked post as solved.