I found the following web page which describes how to construct a power supply for the PI - http://elinux.org/RPi_5V_PSU_construction
A few things I've noticed that I am slightly puzzled for example there is a resistor network applied to an 7805 to increase the output voltage to 5.27volts.
At the bottom of the page there is also the mention of creating 5.75volts from a 7805 regulator.
My understanding is the PI only needs 5v so why the increase in output voltage??
Furthermore the circuit also has 340ohms (10 + 330) connected in series with the output of the regulator this seems crazy to me because you are wasting a lot of energy as heat.
If you need to increase the output voltage of the 7805 regulator why not use replace the 10ohm resistor with a schottky diode for 5.3v output or a silicon rectifier diode for 5.7v output and do away with the 330ohm resistor??
This circuit also includes a transient suppressor but why is the fuse after and not before surely if the regulator goes bad the fuse needs to blow asap not if you're exceeding the current requirement from the output terminals??
Richard S.