WHY MEMORY POSITIONS DO NOT APPEAR IN HEXADECIMAL

[Alberto Rosello]

is a small program of direction visualization of an array of 10 numbers through pointers, as you know a pointer must store the consecutive addresses of the arrangement, but I get the surprise that for example jumps from position 68 to 72 and passes overlook position 6C (hexadecimal numbers are not listed !!!)

Can someone please explain this to me?

I enclose the result where the memory addresses are shown

[procount]

Maybe because ALL the memory addresses are being shown in decimal?

(Hexadecimal numbers without letters are not the same as decimal numbers - they are still hexadecimal. They are usually prefixed with 0x so you can tell the difference and interpret them correctly.)

[Heater]

I'm pretty sure all those numbers are decimal. Notice how the increment by 4 each time, which is what we might expect if the pointer is to integer data or machine instructions.

How are you printing those numbers?

If you are using printf() from C, for example, you will need the correct format specifier for hexadecimal output. Google it.

Why is you post title all in upper case characters?

[6by9]

If you are using printf() from C, for example, you will need the correct format specifier for hexadecimal output. Google it.

Or do

Code: Select all

man 3 printf

to print out the manual page for printf.